新增是否组套,出入库明细改造,

dev_ksck_axxyy
anthonywj 11 months ago
parent b3006e5870
commit 202f3c8959

@ -185,6 +185,7 @@ public class IoOrderDetailResultResponse {
//金额 //金额
private BigDecimal amount; private BigDecimal amount;
private Boolean isStack;
private String invoiceEncode; private String invoiceEncode;

@ -24,17 +24,20 @@
</select> </select>
<select id="filterOrderList" resultType="com.glxp.api.res.inout.IoOrderDetailResultResponse"> <select id="filterOrderList" resultType="com.glxp.api.res.inout.IoOrderDetailResultResponse">
SELECT a2.*, SELECT
a2.*,
a1.mainAction, a1.mainAction,
GROUP_CONCAT(ioi.invoiceEncode ORDER BY ioi.invoiceEncode SEPARATOR ',') as invoiceCodes, bu.isStack,
b1.NAME AS fromCorpName, GROUP_CONCAT( ioi.invoiceEncode ORDER BY ioi.invoiceEncode SEPARATOR ',' ) AS invoiceCodes,
(SELECT NAME FROM basic_bussiness_type bus WHERE bus.action = a1.action) billTypeName b1.NAME AS fromCorpName
FROM io_order_detail_result a2 ,basic_bussiness_type.name billTypeName
FROM
io_order_detail_result a2
LEFT JOIN io_order a1 ON a1.billNo = a2.orderIdFk LEFT JOIN io_order a1 ON a1.billNo = a2.orderIdFk
LEFT JOIN basic_corp b1 ON b1.erpId = a1.fromCorp LEFT JOIN basic_corp b1 ON b1.erpId = a1.fromCorp
left join basic_udirel bu on a2.bindRlFk = bu.id LEFT JOIN basic_udirel bu ON a2.bindRlFk = bu.id
left join io_order_invoice ioi on a1.billNo = ioi.orderIdFk left join basic_bussiness_type on a1.action = basic_bussiness_type.action
LEFT JOIN io_order_invoice ioi ON a1.billNo = ioi.orderIdFk
<where> <where>
a1.status = 7 a1.status = 7
<if test="orderIdFk != null and orderIdFk != ''"> <if test="orderIdFk != null and orderIdFk != ''">

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